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MHT CET 2024 (15 May, Shift 1) · Thermodynamic Processes

Thermodynamic Processes question from MHT CET 2024 (15 May, Shift 1)

Q103MHT CET 2024 · 15 MAY · SHIFT 1Medium

Thermodynamic Processes

The internal energy of an ideal diatomic gas corresponding to volume ' VV ' and pressure ' P ' is 2.5 PV. The gas expands from 1 litre to 2 litre at a constant pressure of 105 N/m210^{5}\text{ N/m}^2. The heat supplied to a gas is

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Answer: (a)

  1. U=2.5PV⇒ΔU=2.5PΔVU = 2.5PV \Rightarrow \Delta U = 2.5P\Delta V at constant PP.
  2. PΔV=105×(2−1)×10−3=100 JP\Delta V = 10^5 \times (2 - 1)\times10^{-3} = 100\text{ J}, so W=100 JW = 100\text{ J}, ΔU=250 J\Delta U = 250\text{ J}.
  3. Q=ΔU+W=250+100=350 JQ = \Delta U + W = 250 + 100 = 350\text{ J}
  4. So the answer is (a) 350 J.
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