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JEE Main 2021 (26 Feb, Shift 2) · Degrees of Freedom & Internal Energy

Degrees of Freedom & Internal Energy question from JEE Main 2021 (26 Feb, Shift 2)

Q26JEE Main 2021 · 26 FEB · SHIFT 2Medium

Degrees of Freedom & Internal Energy

The internal energy (U), pressure (P) and volume (V) of an ideal gas are related as U == 3PV + 4. The gas is:

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Answer: (c)

  1. For an ideal gas U=f2nRT=f2PVU = \frac{f}{2}nRT = \frac{f}{2}PV (plus a constant).
  2. Compare with U=3PV+4U = 3PV + 4: f2=3⇒f=6\frac{f}{2} = 3 \Rightarrow f = 6.
  3. f=6f = 6 means 3 translational + 3 rotational: a non-linear polyatomic gas.
  4. So the answer is (c) polyatomic only.
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