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NEET 2013 · Cells: EMF, Internal Resistance & Combinations

Cells: EMF, Internal Resistance & Combinations question from NEET 2013

Q41NEET 2013Easy

Cells: EMF, Internal Resistance & Combinations

The internal resistance of a 2.1 V cell which gives a current of 0.2 A through a resistance of 10 $\Omega$ is

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Answer: (d)

$I = \frac{E}{R + r} \Rightarrow R + r = \frac{2.1}{0.2} = 10.5\ \Omega$
$r = 10.5 - 10 = 0.5\ \Omega$ . So the answer is (d) $0.5\ \Omega$ .

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