The internal resistance of a cell of emf 2 V is 0.1 Ω. It is connected to a resistance of 3.9 Ω. The voltage across the cell will be (a) 0.5 V (b) 1.9 V (c) 1.95 V (d) 2 V

Answer: (c). I = (2)/(3.9 + 0.1) = 0.5 A Terminal voltage V = E - Ir = 2 - 0.5 × 0.1 = 1.95 V So the answer is (c) 1.95 V.

The internal resistance of a cell of emf 2 V is 0.1 Ω. It is… | NEET 1999 (AIPMT)

Q53NEET 1999 · AIPMTEasy

Cells: EMF, Internal Resistance & Combinations

The internal resistance of a cell of emf $2\text{ V}$ is $0.1\ \Omega$ . It is connected to a resistance of $3.9\ \Omega$ . The voltage across the cell will be

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Answer: (c)

$I = \frac{2}{3.9 + 0.1} = 0.5\text{ A}$
Terminal voltage $V = E - Ir = 2 - 0.5 \times 0.1 = 1.95\text{ V}$
So the answer is (c) 1.95 V.

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