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NEET 2009 (AIPMT) · Transitions, Photon Emission & Excitation

Transitions, Photon Emission & Excitation question from NEET 2009 (AIPMT)

Q74NEET 2009 · AIPMTMedium

Transitions, Photon Emission & Excitation

The ionization energy of the electron in the hydrogen atom in its ground state is 13.6 eV. The atoms are excited to higher energy levels to emit radiations of 6 wavelengths. Maximum wavelength of emitted radiation corresponds to the transition between

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Answer: (c)

Number of lines $\frac{n(n-1)}{2} = 6 \Rightarrow n = 4$ .
Maximum wavelength means minimum energy gap, which is between the two highest levels.
So the answer is (c) $n = 4$ to $n = 3$ .

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