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MHT CET 2019 (2 May, Shift 1) · Satellite Energy & Weightlessness

Satellite Energy & Weightlessness question from MHT CET 2019 (2 May, Shift 1)

Q25MHT CET 2019 · 2 MAY · SHIFT 1Easy

Satellite Energy & Weightlessness

The kinetic energy of a revolving satellite (mass $m$ ) at a height equal to thrice the radius of the earth $(R)$ is

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Answer: (a)

Orbit radius $r = R + 3R = 4R$ .
$K = \frac{GMm}{2r} = \frac{gR^2 m}{2(4R)}$ using $GM = gR^2$ .
$K = \frac{mgR}{8}$ .
So the answer is (a).

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