Energy in SHM question from JEE Main 2026 (21 Jan, Shift 2)

Answer: (b)

1. $K = \frac{1}{2}m\omega^2A^2\cos^2\omega t = \frac{1}{4}m\omega^2A^2(1 + \cos 2\omega t)$, so KE oscillates at $2\omega$.
2. $2\omega = 176 \Rightarrow \omega = 88$ rad/s
3. $f = \frac{\omega}{2\pi} = \frac{88 \times 7}{2 \times 22} = 14$ Hz
4. So the answer is (b) 14 Hz.