The kinetic energy of an ideal gas is E₀ at 27° C. When the temperature is increased to 177° C, then kinetic energy will be (a) E₀/2 (b) 2E₀/3 (c) 3E₀/2 (d) 2E₀

Answer: (c). KE ∝ T (kelvin). T₁ = 300 K, T₂ = 177 + 273 = 450 K E = E₀ × (450)/(300) = 3/2E₀ So the answer is (c) 3E₀/2.

The kinetic energy of an ideal gas is E₀ at 27° C. When the… | MHT CET 2026 (19 Apr, Shift 1)

Q3MHT CET 2026 · 19 APR · SHIFT 1Easy

Pressure & Kinetic Energy of a Gas

The kinetic energy of an ideal gas is $E_0$ at $27^\circ$ C. When the temperature is increased to $177^\circ$ C, then kinetic energy will be

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Answer: (c)

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