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JEE Main 2003 (AIEEE) · Ohm's Law, Resistivity & Temperature

Ohm's Law, Resistivity & Temperature question from JEE Main 2003 (AIEEE)

Q71JEE Main 2003 · AIEEEEasy

Ohm's Law, Resistivity & Temperature

The length of a given cylindrical wire is increased by 100%100\%. Due to the consequent decrease in diameter the change in the resistance of the wire will be

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Answer: (d)

  1. Length increased by 100%100\%: l′=2ll' = 2l.
  2. At constant volume R∝l2R \propto l^2, so R′=4RR' = 4R.
  3. Change =4R−RR×100=300%= \dfrac{4R - R}{R} \times 100 = 300\%
  4. So the answer is (d) 300%300\%.
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