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JEE Main 2022 (25 Jun, Shift 2) · Ohm's Law, Resistivity & Temperature

Ohm's Law, Resistivity & Temperature question from JEE Main 2022 (25 Jun, Shift 2)

Q27JEE Main 2022 · 25 JUN · SHIFT 2Easy

Ohm's Law, Resistivity & Temperature

The length of a given cylindrical wire is increased to double of its original length. The percentage increase in the resistance of the wire will be ____________ %.

Numerical answer type. Work it out, then open the answer.

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Answer: 300

  1. l′=2ll' = 2l; at constant volume R∝l2R \propto l^2, so R′=4RR' = 4R.
  2. Percentage increase =4R−RR×100= \dfrac{4R - R}{R} \times 100
  3. Answer: 300%300\%.
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