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JEE Main 2025 (2 Apr, Shift 2) · Wire Combinations & Special Cases

Wire Combinations & Special Cases question from JEE Main 2025 (2 Apr, Shift 2)

Q4JEE Main 2025 · 2 APR · SHIFT 2Medium

Wire Combinations & Special Cases

The length of a light string is 1.4 m when the tension on it is 5 N. If the tension increases to 7 N, the length of the string is 1.56 m. The original length of the string is__________m.

Numerical answer type. Work it out, then open the answer.

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Answer: 1

  1. L=l1T2−l2T1T2−T1L = \frac{l_1T_2 - l_2T_1}{T_2 - T_1}
  2. L=1.4×7−1.56×57−5=9.8−7.82L = \frac{1.4 \times 7 - 1.56 \times 5}{7 - 5} = \frac{9.8 - 7.8}{2}
  3. L=1 mL = 1\text{ m}
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