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JEE Main 2003 (AIEEE) · Simple Pendulum

Simple Pendulum question from JEE Main 2003 (AIEEE)

Q82JEE Main 2003 · AIEEEEasy

Simple Pendulum

The length of a simple pendulum executing simple harmonic motion is increased by $21\%$ . The percentage increase in the time period of the pendulum of increased length is

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Answer: (d)

$T \propto \sqrt{l}$ ; $l' = 1.21\,l$
$T' = \sqrt{1.21}\,T = 1.1\,T$
Increase $= 10\%$ (exact, since the change is not small, the $\frac{1}{2}\times 21\%$ approximation is not used).
So the answer is (d) $10\%$ .

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