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MHT CET 2024 (10 May, Shift 2) · Stationary Waves & Vibrating Strings

Stationary Waves & Vibrating Strings question from MHT CET 2024 (10 May, Shift 2)

Q46MHT CET 2024 · 10 MAY · SHIFT 2Easy

Stationary Waves & Vibrating Strings

The length of a sonometer wire 'AB' is 110 cm. Where should the two bridges be placed from end ' $A$ ' to divide the wire in three segments whose fundamental frequencies are in the ratio $1:2:3$ ?

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Answer: (a)

$f \propto \dfrac{1}{l}$ : $l_1 : l_2 : l_3 = 1 : \dfrac{1}{2} : \dfrac{1}{3} = 6 : 3 : 2$ .
Each part $= \dfrac{110}{11} = 10\text{ cm} \Rightarrow 60, 30, 20\text{ cm}$ .
Bridges from A at $60\text{ cm}$ and $60 + 30 = 90\text{ cm}$ .
So the answer is (a) 60 cm and 90 cm.

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