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MHT CET 2025 (20 Apr, Shift 2) · Organ Pipes & Resonance Tube

Organ Pipes & Resonance Tube question from MHT CET 2025 (20 Apr, Shift 2)

Q39MHT CET 2025 · 20 APR · SHIFT 2Medium

Organ Pipes & Resonance Tube

The length of closed and open pipe is same. The ratio of frequency of $n$ th overtone for closed pipe to that of open pipe is (Neglect end correction)

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Answer: (a)

Closed pipe, $n$ th overtone $= (2n+1)$ th harmonic: $\frac{(2n+1)v}{4L}$ .
Open pipe, $n$ th overtone $= (n+1)$ th harmonic: $\frac{(n+1)v}{2L}$ .
Ratio $= \frac{(2n+1)}{2(n+1)}$
So the answer is (a) $\frac{(2n+1)}{2(n+1)}$ .

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