The length of mercury column in a mercury-in-glass thermometer is H₁ mm at the ice point and H₂ mm at the steam point. When the length is H mm, the temperature T is given in ° C by ( H₁ < H₂) (a) (100(H - H₁))/((H₂ - H₁)) (b) (100(H₂ - H))/((H₂ - H₁)) (c) (100(H₂ - H₁))/((H - H₁)) (d) (100(H₂ - H))/((H - H₁))

Answer: (a). Mercury length rises linearly with temperature: (T-0)/(100-0)=(H-H₁)/(H₂-H₁). So the answer is (a) T=(100(H-H₁))/(H₂-H₁).

The length of mercury column in a mercury-in-glass thermometer is H₁… | MHT CET 2026 (19 May, Shift 1)

Q1MHT CET 2026 · 19 MAY · SHIFT 1Easy

Thermometry & Thermal Expansion

The length of mercury column in a mercury-in-glass thermometer is $H_1$ mm at the ice point and $H_2$ mm at the steam point. When the length is $H$ mm, the temperature $T$ is given in $^\circ$ C by ( $H_1 < H_2$ )

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Answer: (a)

Mercury length rises linearly with temperature: $\frac{T-0}{100-0}=\frac{H-H_1}{H_2-H_1}$ .
So the answer is (a) $T=\frac{100(H-H_1)}{H_2-H_1}$ .

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Thermometry & Thermal Expansion question from MHT CET 2026 (19 May, Shift 1)

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