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MHT CET 2025 (22 Apr, Shift 2) · Beats

Beats question from MHT CET 2025 (22 Apr, Shift 2)

Q25MHT CET 2025 · 22 APR · SHIFT 2Medium

Beats

The lengths of the two organ pipes open at both ends are ' L ' and (L+L1)(L + L_1). If they are sounded together, the beat frequency will be ( v=v = velocity of sound in air)

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Answer: (d)

  1. Open pipe fundamental: f=v2Lf = \frac{v}{2L}.
  2. Beat frequency =v2L−v2(L+L1)=v2⋅L1L(L+L1)= \frac{v}{2L} - \frac{v}{2(L+L_1)} = \frac{v}{2}\cdot\frac{L_1}{L(L+L_1)}
  3. So the answer is (d) vL12L(L+L1)\frac{vL_1}{2L(L+L_1)}.
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