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MHT CET 2026 (18 Apr, Shift 1) · Beats

Beats question from MHT CET 2026 (18 Apr, Shift 1)

Q13MHT CET 2026 · 18 APR · SHIFT 1Medium

Beats

The lengths of the two pipes open at both ends are L and (L+L1)(L + L_1). If they are sounded together, the beat frequency will be

(vv = velocity of sound in air)

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Answer: (d)

  1. Open pipe fundamental: f=v2Lf = \frac{v}{2L}.
  2. f1=v2Lf_1 = \frac{v}{2L}, f2=v2(L+L1)f_2 = \frac{v}{2(L+L_1)}
  3. Beat frequency =f1−f2=v2[1L−1L+L1]=vL12L(L+L1)= f_1 - f_2 = \frac{v}{2}\left[\frac{1}{L} - \frac{1}{L+L_1}\right] = \frac{vL_1}{2L(L+L_1)}
  4. So the answer is (d) vL12L(L+L1)\frac{vL_1}{2L(L+L_1)}.
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