The lens combination as shown in the figure, consists of two lenses, L₁ and L₂, of the focal lengths +10 cm and -10 cm, respectively. The position of the image formed is: (a) 60 cm to the right of the concave lens (b) 20 cm to the left of the concave lens (c) 60 cm to the left of the concave lens (d) 30 cm to the right of the concave lens

Answer: (c). L₁: u = -30, f = +10: 1/v = 1/10 - 1/30 ⇒ v = 15 cm. This image is 15 - 3 = 12 cm right of L₂: virtual object, u = +12. L₂: 1/v = -1/10 + 1/12 = -1/60 ⇒ v = -60 cm So the answer is (c) 60 cm to the left of the concave lens.

The lens combination as shown in the figure, consists of two lenses… | NEET 2026 (Re-neet)

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Combination of Lenses

The lens combination as shown in the figure, consists of two lenses, $L_1$ and $L_2$ , of the focal lengths +10 cm and -10 cm, respectively. The position of the image formed is:

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Answer: (c)

$L_1$ : $u = -30$ , $f = +10$ : $\frac{1}{v} = \frac{1}{10} - \frac{1}{30} \Rightarrow v = 15\text{ cm}$ .
This image is $15 - 3 = 12\text{ cm}$ right of $L_2$ : virtual object, $u = +12$ .
$L_2$ : $\frac{1}{v} = -\frac{1}{10} + \frac{1}{12} = -\frac{1}{60} \Rightarrow v = -60\text{ cm}$
So the answer is (c) 60 cm to the left of the concave lens.

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