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MHT CET 2021 (22 Sep, Shift 2) · Photoelectric Effect: Einstein's Equation

Photoelectric Effect: Einstein's Equation question from MHT CET 2021 (22 Sep, Shift 2)

Q101MHT CET 2021 · 22 SEP · SHIFT 2Easy

Photoelectric Effect: Einstein's Equation

The light of wavelength 'λ\lambda' is incident on the surface of metal of work function ϕ\phi and emits the electron. The maximum velocity of electron emitted is [m=m = mass of electron and h=h = Planck's constant, c=c = velocity of light]

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Answer: (d)

  1. 12mvmax2=hcλ−ϕ=hc−λϕλ\frac{1}{2}mv_{max}^2 = \frac{hc}{\lambda} - \phi = \frac{hc - \lambda\phi}{\lambda}
  2. vmax=[2(hc−λϕ)mλ]1/2v_{max} = \left[\frac{2(hc - \lambda\phi)}{m\lambda}\right]^{1/2}
  3. So the answer is (d).
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