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MHT CET 2024 (16 May, Shift 2) · Angular Variables

Angular Variables question from MHT CET 2024 (16 May, Shift 2)

Q19MHT CET 2024 · 16 MAY · SHIFT 2Medium

Angular Variables

The linear speed of a particle at the equator of the earth due to its spin motion is ' V '. The linear speed of the particle at latitude 30∘30^\circ is

[sin⁡30∘=cos⁡60∘=1/2cos⁡30∘=sin⁡60∘=3/2]\left[\begin{matrix} \sin 30^\circ = \cos 60^\circ = 1/2 \\ \cos 30^\circ = \sin 60^\circ = \sqrt{3}/2 \end{matrix}\right]

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Answer: (c)

  1. At latitude λ\lambda the radius of the circle is Rcos⁡λR\cos\lambda, and ω\omega is the same.
  2. v=ωRcos⁡λ=Vcos⁡30∘=32Vv = \omega R\cos\lambda = V\cos 30^\circ = \frac{\sqrt3}{2}V.
  3. So the answer is (c) 32V\frac{\sqrt{3}}{2}V.
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