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JEE Main 2021 (24 Feb, Shift 2) · Logic Gates

Logic Gates question from JEE Main 2021 (24 Feb, Shift 2)

Q135JEE Main 2021 · 24 FEB · SHIFT 2Medium

Logic Gates

The logic circuit shown above is equivalent to:

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Answer: (d)

OR gate inputs are $A$ and $\bar{B}$ , then NOT: $C = \overline{A + \bar{B}}$ .
De Morgan: $C = \bar{A} \cdot B$ .
This is an AND gate with $A$ passed through a NOT gate.
So the answer is (d).

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