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JEE Main 2019 (9 Apr, Shift 2) · Logic Gates

Logic Gates question from JEE Main 2019 (9 Apr, Shift 2)

Q150JEE Main 2019 · 9 APR · SHIFT 2Medium

Logic Gates

The logic gate equivalent to the given logic circuit is :-

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Answer: (d)

The NOT gates give $\bar{A}$ and $\bar{B}$ , which feed a NAND gate.
$Y = \overline{\bar{A} \cdot \bar{B}} = A + B$ (De Morgan).
So the answer is (d) OR.

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