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JEE Main 2024 (6 Apr, Shift 2) · Hydrogen Spectrum & Spectral Series

Hydrogen Spectrum & Spectral Series question from JEE Main 2024 (6 Apr, Shift 2)

Q23JEE Main 2024 · 6 APR · SHIFT 2Medium

Hydrogen Spectrum & Spectral Series

The longest wavelength associated with Paschen series is: (Given RH=1.097×107 SIR_H = 1.097 \times 10^{7}\text{ SI} unit)

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Answer: (b)

  1. Paschen longest (4→34 \to 3): 1λ=R(19−116)=7R144\frac{1}{\lambda} = R\left(\frac{1}{9}-\frac{1}{16}\right) = \frac{7R}{144}
  2. λ=1447×1.097×107\lambda = \frac{144}{7\times 1.097\times 10^{7}}
  3. λ≈1.876×10−6\lambda \approx 1.876\times 10^{-6} m
  4. So the answer is (b) 1.876×10−61.876 \times 10^{-6} m.
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