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MHT CET 2024 (2 May, Shift 2) · Pure R, L and C Circuits

Pure R, L and C Circuits question from MHT CET 2024 (2 May, Shift 2)

Q30MHT CET 2024 · 2 MAY · SHIFT 2Medium

Pure R, L and C Circuits

The magnetic energy in an inductor changes from maximum value to minimum value in 5 ms. When connected to an a.c. source, the frequency of the source is

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Answer: (a)

  1. Magnetic energy U=12LI2U = \frac{1}{2}LI^2 goes from maximum (I=I0I = I_0) to zero (I=0I = 0) in a quarter period.
  2. T4=5\frac{T}{4} = 5 ms ⇒T=20\Rightarrow T = 20 ms
  3. f=1T=10.02=50f = \frac{1}{T} = \frac{1}{0.02} = 50 Hz
  4. So the answer is (a) 50 Hz.
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