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MHT CET 2026 (19 Apr, Shift 2) · Self-Inductance & Energy

Self-Inductance & Energy question from MHT CET 2026 (19 Apr, Shift 2)

Q10MHT CET 2026 · 19 APR · SHIFT 2Easy

Self-Inductance & Energy

The magnetic energy stored in an inductor of inductance $4$ H carrying a current of $1.5$ A is

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Answer: (d)

$U = \tfrac12 L I^2$
$U = \tfrac12\times4\times(1.5)^2 = 2\times2.25 = 4.5\text{ J}$
$4.5\text{ J} = 4500\text{ mJ}$
So the answer is (d) $4500$ mJ.

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