The magnetic energy stored in an inductor of inductance 4 carrying a current of 2 A is: (a) 4 mJ (b) 8 mJ (c) 8 (d) 4

Answer: (c). U = 1/2LI² U = 1/2(4×10⁻⁶)(2)² = 8×10⁻⁶ J So the answer is (c) 8.

The magnetic energy stored in an inductor of inductance 4 carrying a… | NEET 2023

Q4NEET 2023Easy

Inductors & DC Transients (Mixed)

The magnetic energy stored in an inductor of inductance $4\,\mu\text{H}$ carrying a current of $2\text{ A}$ is:

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Answer: (c)

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