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MHT CET 2026 (17 Apr, Shift 1) · Magnetic Field of Straight Wires

Magnetic Field of Straight Wires question from MHT CET 2026 (17 Apr, Shift 1)

Q3MHT CET 2026 · 17 APR · SHIFT 1Easy

Magnetic Field of Straight Wires

The magnetic field at perpendicular distance 'rr' from a long wire carrying current 'II' is 'BB'. The magnetic field at perpendicular distance '2r2r' from the same wire is

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Answer: (b)

  1. B=μ0I2πr⇒B∝1rB = \dfrac{\mu_0 I}{2\pi r} \Rightarrow B \propto \dfrac{1}{r}
  2. At 2r2r: B′=B2B' = \dfrac{B}{2}
  3. So the answer is (b).
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