The magnetic field at the centre of a current carrying circular coil of area 'A' is 'B'. The magnetic moment of the coil is ( μ₀ = permeability of free space) (a) 2BA3/2μ₀√(π) (b) BA3/2μ₀π (c) μ₀√(π)2BA² (d) 2BA²μ₀√(π)

Answer: (a). B = (μ₀ I)/(2r) ⇒ I = (2Br)/(μ₀), with r = √(A/π). M = IA = (2BA)/(μ₀)√(A/π) So the answer is (a) 2BA3/2μ₀√(π).

The magnetic field at the centre of a current carrying circular coil… | MHT CET 2021 (20 Sep, Shift 2)

Q56MHT CET 2021 · 20 SEP · SHIFT 2Medium

Current Loop as a Magnetic Dipole

The magnetic field at the centre of a current carrying circular coil of area 'A' is 'B'. The magnetic moment of the coil is ( $\mu_0 =$ permeability of free space)

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Answer: (a)

$B = \frac{\mu_0 I}{2r} \Rightarrow I = \frac{2Br}{\mu_0}$ , with $r = \sqrt{A/\pi}$ .
$M = IA = \frac{2BA}{\mu_0}\sqrt{\frac{A}{\pi}}$
So the answer is (a) $\frac{2BA^{3/2}}{\mu_0\sqrt{\pi}}$ .

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Current Loop as a Magnetic Dipole question from MHT CET 2021 (20 Sep, Shift 2)

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