The magnetic field at the centre of a current carrying circular coil of area ' A ' is ' B '. The magnetic moment of the coil is ( μ₀ = permeability of free space) (a) 2μ₀π1/2BA3/2 (b) BA3/2μ₀π (c) 2BA3/2μ₀π1/2 (d) (BA²)/(μ₀π)

Answer: (c). I = (2Br)/(μ₀) with r = √(A/π). M = IA = (2BA)/(μ₀)√(A/π) So the answer is (c) 2BA3/2μ₀π1/2.

The magnetic field at the centre of a current carrying circular coil… | MHT CET 2024 (2 May, Shift 1)

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Current Loop as a Magnetic Dipole

The magnetic field at the centre of a current carrying circular coil of area ' $A$ ' is ' $B$ '. The magnetic moment of the coil is ( $\mu_0 =$ permeability of free space)

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Answer: (c)

$I = \frac{2Br}{\mu_0}$ with $r = \sqrt{A/\pi}$ .
$M = IA = \frac{2BA}{\mu_0}\sqrt{\frac{A}{\pi}}$
So the answer is (c) $\frac{2BA^{3/2}}{\mu_0\pi^{1/2}}$ .

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