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MHT CET 2025 (23 Apr, Shift 1) · Current Loop as a Magnetic Dipole

Current Loop as a Magnetic Dipole question from MHT CET 2025 (23 Apr, Shift 1)

Q24MHT CET 2025 · 23 APR · SHIFT 1Medium

Current Loop as a Magnetic Dipole

The magnetic field at the centre of a current carrying circular coil of area ' AA ' is ' BB '. The magnetic moment ( M) of the coil is ( μ0=\mu_0 = permeability of free space)

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Answer: (b)

  1. B=μ0I2r⇒I=2Brμ0B = \frac{\mu_0 I}{2r} \Rightarrow I = \frac{2Br}{\mu_0}, and A=πr2⇒r=A/πA = \pi r^2 \Rightarrow r = \sqrt{A/\pi}.
  2. M=IA=2BrAμ0=2BAμ0AπM = IA = \frac{2BrA}{\mu_0} = \frac{2BA}{\mu_0}\sqrt{\frac{A}{\pi}}
  3. So the answer is (b) 2BA3/2μ0π\frac{2BA^{3/2}}{\mu_0\sqrt{\pi}}.
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