The magnetic field (B) inside a long solenoid having ' n ' turns per unit length and carrying current ' i ' when iron core is kept in it, is ( μ₀ = permeability of vacuum, χ = magnetic susceptibility) (a) μ₀ ni(1 + χ) (b) μ₀ ni²(1 + χ) (c) μ₀ niχ (d) μ₀ ni(1 - χ)

Answer: (a). Without core B₀ = μ₀ n i; the core multiplies it by μr. B = μ₀μr n i = μ₀ n i(1+χ) So the answer is (a).

The magnetic field (B) inside a long solenoid having ' n ' turns per… | MHT CET 2025 (5 May, Shift 2)

Q17MHT CET 2025 · 5 MAY · SHIFT 2Easy

Magnetisation: B, H, M, χ & μ

The magnetic field (B) inside a long solenoid having ' $n$ ' turns per unit length and carrying current ' i ' when iron core is kept in it, is ( $\mu_0 =$ permeability of vacuum, $\chi =$ magnetic susceptibility)

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Answer: (a)

Without core $B_0 = \mu_0 n i$ ; the core multiplies it by $\mu_r$ .
$B = \mu_0\mu_r n i = \mu_0 n i(1+\chi)$
So the answer is (a).

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Magnetisation: B, H, M, χ & μ question from MHT CET 2025 (5 May, Shift 2)

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