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NEET 2020 (Phase 2) · Nature of EM Waves & Wave Equation

Nature of EM Waves & Wave Equation question from NEET 2020 (Phase 2)

Q50NEET 2020 · PHASE 2Easy

Nature of EM Waves & Wave Equation

The magnetic field in a plane electromagnetic wave is given by,

By=2×10−7sin⁡(π×103x+3π×1011t) TB_y = 2\times 10^{-7}\sin(\pi\times 10^{3}x + 3\pi\times 10^{11}t)\text{ T}

Calculate the wavelength.

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Answer: (c)

  1. Compare with B0sin⁡(kx+ωt)B_0\sin(kx+\omega t): k=π×103 m−1k = \pi\times 10^{3}\ \text{m}^{-1}.
  2. λ=2πk=2ππ×103\lambda = \frac{2\pi}{k} = \frac{2\pi}{\pi\times 10^{3}}.
  3. λ=2×10−3 m\lambda = 2\times 10^{-3}\ \text{m}.
  4. So the answer is (c).
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