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MHT CET 2021 (22 Sep, Shift 2) · Ampere's Law, Cylinders, Solenoid & Toroid

Ampere's Law, Cylinders, Solenoid & Toroid question from MHT CET 2021 (22 Sep, Shift 2)

Q44MHT CET 2021 · 22 SEP · SHIFT 2Medium

Ampere's Law, Cylinders, Solenoid & Toroid

The magnetic field inside a current carrying toroidal solenoid is 0.2 mT0.2\text{ mT}. What is the magnetic field inside the toroid if the current through it is tripled and radius is made 13\frac{1}{3}rd?

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Answer: (b)

  1. Inside a toroid B=μ0nIB = \mu_0 n I, where nn is the number of turns per unit length.
  2. With the same winding density nn, BB does not depend on the radius, so B∝IB \propto I.
  3. B′=3×0.2=0.6B' = 3 \times 0.2 = 0.6 mT
  4. So the answer is (b) 0.6 mT.
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