the magnetic flux (in weber) in a closed circuit of resistance 20 Ω varies with time t second according to equation φ = 5t² - 6t + 9. The magnitude of induced current at t = 0.2 second is (a) 0.8 A (b) 1 A (c) 0.2 A (d) 0.4 A

Answer: (c). (dφ)/(dt) = 10t - 6; at t = 0.2 s, (dφ)/(dt) = 2 - 6 = -4 Wb/s, so |e| = 4 V I = |e|/R = 4/20 = 0.2 A So the answer is (c) 0.2 A.

the magnetic flux (in weber) in a closed circuit of resistance 20 Ω… | MHT CET 2021 (22 Sep, Shift 2)

Q62MHT CET 2021 · 22 SEP · SHIFT 2Easy

Magnetic Flux & Faraday's Law

the magnetic flux (in weber) in a closed circuit of resistance $20\,\Omega$ varies with time $t$ second according to equation $\phi = 5t^{2} - 6t + 9$ . The magnitude of induced current at $t = 0.2$ second is

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Answer: (c)

$\frac{d\phi}{dt} = 10t - 6$ ; at $t = 0.2$ s, $\frac{d\phi}{dt} = 2 - 6 = -4$ Wb/s, so $|e| = 4$ V
$I = \frac{|e|}{R} = \frac{4}{20} = 0.2$ A
So the answer is (c) 0.2 A.

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