The magnetic flux φ (in weber) linked with a closed circuit of resistance 8 Ω varies with time (in seconds) as φ = 5t² - 36t + 1. The induced current in the circuit at t = 2 s is __________ A. Numerical answer type. Work it out, then open the answer.

Answer: 2. (dφ)/(dt) = 10t - 36; at t = 2 s, (dφ)/(dt) = 20 - 36 = -16 Wb/s, so |e| = 16 V I = |e|/R = 16/8 = 2 A So the answer is 2 A.

The magnetic flux φ (in weber) linked with a closed circuit of… | JEE Main 2024 (31 Jan, Shift 2)

Q34JEE Main 2024 · 31 JAN · SHIFT 2Easy

Magnetic Flux & Faraday's Law

The magnetic flux $\phi$ (in weber) linked with a closed circuit of resistance $8\,\Omega$ varies with time (in seconds) as $\phi = 5t^{2} - 36t + 1$ . The induced current in the circuit at $t = 2\text{ s}$ is __________ A.

Numerical answer type. Work it out, then open the answer.

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Answer: 2

$\frac{d\phi}{dt} = 10t - 36$ ; at $t = 2$ s, $\frac{d\phi}{dt} = 20 - 36 = -16$ Wb/s, so $|e| = 16$ V
$I = \frac{|e|}{R} = \frac{16}{8} = 2$ A
So the answer is 2 A.

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