The magnetic flux linked to a circular coil of radius R is φ = 2t³ + 4t² + 2t + 5 Wb The magnitude of induced emf in the coil at t = 5 s is (a) 192 V (b) 108 V (c) 197 V (d) 150 V

Answer: (a). |e| = (dφ)/(dt) = 6t² + 8t + 2 At t = 5 s: |e| = 150 + 40 + 2 = 192 V So the answer is (a) 192 V.

The magnetic flux linked to a circular coil of radius R is φ = 2t³ +… | NEET 2022 (Phase 2)

Q53NEET 2022 · PHASE 2Easy

Magnetic Flux & Faraday's Law

The magnetic flux linked to a circular coil of radius R is

$\phi = 2t^{3} + 4t^{2} + 2t + 5$ Wb

The magnitude of induced emf in the coil at t = 5 s is

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Answer: (a)

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