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NEET 2020 (Phase 2) · Magnetic Flux & Faraday's Law

Magnetic Flux & Faraday's Law question from NEET 2020 (Phase 2)

Q68NEET 2020 · PHASE 2Easy

Magnetic Flux & Faraday's Law

The magnetic flux linked with a coil (in Wb) is given by the equation

ϕ=5t2+3t+16\phi = 5t^{2} + 3t + 16

The magnitude of induced emf in the coil at the fourth second will be

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Answer: (c)

  1. ∣e∣=dϕdt=10t+3|e| = \frac{d\phi}{dt} = 10t + 3
  2. At t=4t = 4 s: ∣e∣=40+3=43|e| = 40 + 3 = 43 V
  3. So the answer is (c) 4343 V.
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