The magnetic flux through a circuit of resistance ' R ' changes by an amount Δφ in the time Δ t. The total quantity of electric charge ' Q ' which passes during this time through any point of the circuit is (a) -(Δφ)/(Δ t) + R (b) (Δφ)/(R) (c) (Δφ)/(Δ t) (d) (Δφ)/(Δ t) × R

Answer: (b). I = 1/R(Δφ)/(Δ t) and Q = IΔ t. Q = (Δφ)/(R), independent of Δ t. So the answer is (b) (Δφ)/(R).

The magnetic flux through a circuit of resistance ' R ' changes by an… | MHT CET 2023 (11 May, Shift 2)

Q46MHT CET 2023 · 11 MAY · SHIFT 2Easy

Magnetic Flux & Faraday's Law

The magnetic flux through a circuit of resistance ' $R$ ' changes by an amount $\Delta\phi$ in the time $\Delta t$ . The total quantity of electric charge ' $Q$ ' which passes during this time through any point of the circuit is

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Answer: (b)

$I = \frac{1}{R}\frac{\Delta\phi}{\Delta t}$ and $Q = I\Delta t$ .
$Q = \frac{\Delta\phi}{R}$ , independent of $\Delta t$ .
So the answer is (b) $\frac{\Delta\phi}{R}$ .

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Magnetic Flux & Faraday's Law question from MHT CET 2023 (11 May, Shift 2)

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