The magnetic flux through a coil of resistance ' R ' changes by an amount ' Δφ ' in time ' Δ t '. The total quantity of induced electric charge ' Q ' is (a) -(Δφ)/(Δ t) + R (b) (Δφ)/(Δ t) × R (c) (Δφ)/(R) (d) (Δφ)/(Δ t)

Answer: (c). I = 1/R(Δφ)/(Δ t) and Q = IΔ t. Q = (Δφ)/(R) So the answer is (c) (Δφ)/(R).

The magnetic flux through a coil of resistance ' R ' changes by an… | MHT CET 2022 (11 Aug, Shift 2)

Q56MHT CET 2022 · 11 AUG · SHIFT 2Easy

Magnetic Flux & Faraday's Law

The magnetic flux through a coil of resistance ' $R$ ' changes by an amount ' $\Delta\phi$ ' in time ' $\Delta t$ '. The total quantity of induced electric charge ' $Q$ ' is

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Answer: (c)

$I = \frac{1}{R}\frac{\Delta\phi}{\Delta t}$ and $Q = I\Delta t$ .
$Q = \frac{\Delta\phi}{R}$
So the answer is (c) $\frac{\Delta\phi}{R}$ .

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Magnetic Flux & Faraday's Law question from MHT CET 2022 (11 Aug, Shift 2)

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