The magnetic flux through a coil of resistance ' R ' changes by an amount Δφ in the time Δ t. The total quantity of induced current and charge is respectively (a) (Δφ)/(Δ t) and (Δφ)/(R) (b) (Δφ)/(Δ t) × R and (Δφ)/(Δ t) (c) (Δφ)/(RΔ t) and (Δφ)/(R) (d) (RΔ t)/(Δφ) and RΔφ

Answer: (c). Average emf e = (Δφ)/(Δ t), so current I = e/R = (Δφ)/(RΔ t). Charge q = IΔ t = (Δφ)/(R). So the answer is (c) (Δφ)/(RΔ t) and (Δφ)/(R).

The magnetic flux through a coil of resistance ' R ' changes by an… | MHT CET 2026 (19 May, Shift 1)

Q9MHT CET 2026 · 19 MAY · SHIFT 1Easy

Magnetic Flux & Faraday's Law

The magnetic flux through a coil of resistance ' $R$ ' changes by an amount $\Delta\phi$ in the time $\Delta t$ . The total quantity of induced current and charge is respectively

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Answer: (c)

Average emf $e = \frac{\Delta\phi}{\Delta t}$ , so current $I = \frac{e}{R} = \frac{\Delta\phi}{R\Delta t}$ .
Charge $q = I\Delta t = \frac{\Delta\phi}{R}$ .
So the answer is (c) $\frac{\Delta\phi}{R\Delta t}$ and $\frac{\Delta\phi}{R}$ .

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Magnetic Flux & Faraday's Law question from MHT CET 2026 (19 May, Shift 1)

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