The magnetic flux through a coil perpendicular to its plane is varying according to the relation φ = (5t³ + 4t² + 2t - 5) Weber. If the resistance of the coil is 5 ohm, then the induced current through the coil at t = 2 s will be, (a) 15.6 A (b) 16.6 A (c) 17.6 A (d) 18.6 A

Answer: (a). |e| = (dφ)/(dt) = 15t² + 8t + 2 At t = 2 s: |e| = 60 + 16 + 2 = 78 V I = 78/5 = 15.6 A So the answer is (a) 15.6 A.

The magnetic flux through a coil perpendicular to its plane is… | JEE Main 2022 (26 Jun, Shift 1)

Q54JEE Main 2022 · 26 JUN · SHIFT 1Easy

Magnetic Flux & Faraday's Law

The magnetic flux through a coil perpendicular to its plane is varying according to the relation $\phi = (5t^{3} + 4t^{2} + 2t - 5)$ Weber. If the resistance of the coil is 5 ohm, then the induced current through the coil at t = 2 s will be,

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Answer: (a)

$|e| = \frac{d\phi}{dt} = 15t^{2} + 8t + 2$
At $t = 2$ s: $|e| = 60 + 16 + 2 = 78$ V
$I = \frac{78}{5} = 15.6$ A
So the answer is (a) 15.6 A.

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