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NEET 1990 (AIPMT) · Magnetic Field of Straight Wires

Magnetic Field of Straight Wires question from NEET 1990 (AIPMT)

Q75NEET 1990 · AIPMTEasy

Magnetic Field of Straight Wires

The magnetic induction at a point PP which is at the distance of 4 cm4\text{ cm} from a long current carrying wire is 10−3 T10^{-3}\text{ T}. The field of induction at a distance 12 cm12\text{ cm} from the current will be

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Answer: (a)

  1. B∝1rB \propto \frac{1}{r} for a long wire.
  2. B′=10−3×412=3.33×10−4 TB' = 10^{-3} \times \frac{4}{12} = 3.33 \times 10^{-4}\text{ T}
  3. So the answer is (a) 3.33×10−4 T3.33 \times 10^{-4}\text{ T}.
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