The magnetic intensity at the center of a long current carrying solenoid is found to be 1.6 × 10³ Am⁻¹. If the number of turns is 8 per cm, then the current flowing through the solenoid is __________ A. Numerical answer type. Work it out, then open the answer.

Answer: 2. H = nI with n = 8 per cm = 800 m⁻¹. I = H/n = 1.6 × 10³800 = 2 So the current is 2 A.

The magnetic intensity at the center of a long current carrying… | JEE Main 2023 (8 Apr, Shift 1)

Q29JEE Main 2023 · 8 APR · SHIFT 1Easy

Magnetisation: B, H, M, χ & μ

The magnetic intensity at the center of a long current carrying solenoid is found to be $1.6 \times 10^{3}\text{ Am}^{-1}$ . If the number of turns is 8 per cm, then the current flowing through the solenoid is __________ A.

Numerical answer type. Work it out, then open the answer.

Show answer and solution

Answer: 2

$H = nI$ with $n = 8\ \text{per cm} = 800\ \text{m}^{-1}$ .
$I = \dfrac{H}{n} = \dfrac{1.6 \times 10^{3}}{800} = 2$
So the current is 2 A.

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