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MHT CET 2025 (26 Apr, Shift 2) · Bohr Model: Orbits, Speed & Angular Momentum

Bohr Model: Orbits, Speed & Angular Momentum question from MHT CET 2025 (26 Apr, Shift 2)

Q37MHT CET 2025 · 26 APR · SHIFT 2Easy

Bohr Model: Orbits, Speed & Angular Momentum

The magnetic moment of electron due to orbital motion is proportional to ( $n =$ principal quantum number)

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Answer: (a)

$\mu = \frac{eL}{2m}$ with $L = \frac{nh}{2\pi}$ .
$\mu = n\frac{eh}{4\pi m} \propto n$
So the answer is (a) $n$ .

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