The magnetic potential energy stored in a certain inductor is 25 mJ, when the current in the inductor is 50 mA. This inductor is of inductance (a) 2.00 H (b) 0.20 H (c) 200 H (d) 20 H

Answer: (d). L = 2U/I² L = 2×25×10⁻³(50×10⁻³)² = 50×10⁻³2.5×10⁻³ L = 20 H So the answer is (d) 20 H.

The magnetic potential energy stored in a certain inductor is 25 mJ… | MHT CET 2021 (21 Sep, Shift 1)

Q70MHT CET 2021 · 21 SEP · SHIFT 1Easy

Self-Inductance & Energy

The magnetic potential energy stored in a certain inductor is $25\text{ mJ}$ , when the current in the inductor is $50\text{ mA}$ . This inductor is of inductance

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Answer: (d)

$L = \dfrac{2U}{I^2}$
$L = \dfrac{2\times25\times10^{-3}}{(50\times10^{-3})^2} = \dfrac{50\times10^{-3}}{2.5\times10^{-3}}$
$L = 20\text{ H}$
So the answer is (d) 20 H.

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