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MHT CET 2026 (18 Apr, Shift 1) · Self-Inductance & Energy

Self-Inductance & Energy question from MHT CET 2026 (18 Apr, Shift 1)

Q12MHT CET 2026 · 18 APR · SHIFT 1Easy

Self-Inductance & Energy

The magnetic potential energy stored in a certain inductor is 4949 mJ when the current in the inductor is 7070 mA. The inductance of the inductor is

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Answer: (c)

  1. U=12LI2⇒L=2UI2U = \tfrac12 L I^2 \Rightarrow L = \dfrac{2U}{I^2}
  2. L=2×49×10−3(70×10−3)2=98×10−34.9×10−3L = \dfrac{2\times49\times10^{-3}}{(70\times10^{-3})^2} = \dfrac{98\times10^{-3}}{4.9\times10^{-3}}
  3. L=20 HL = 20\text{ H}
  4. So the answer is (c) 2020 H.
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