Physics Circle home Student Login

Home›Chapters›Moving Charges and Magnetism PYQs›Other: Induction & Displacement Current›Question 4

MHT CET 2024 (9 May, Shift 2) · Other: Induction & Displacement Current

Other: Induction & Displacement Current question from MHT CET 2024 (9 May, Shift 2)

Q4MHT CET 2024 · 9 MAY · SHIFT 2Easy

Other: Induction & Displacement Current

The magnetic potential energy stored in certain inductor is 64×10−3 J64 \times 10^{-3}\text{ J}, when the current in the inductor is 80 mA. This inductor is of inductance

Show answer and solution

Answer: (c)

  1. Energy in an inductor U=12LI2⇒L=2UI2U = \frac{1}{2}LI^2 \Rightarrow L = \frac{2U}{I^2}.
  2. L=2×64×10−3(80×10−3)2=0.1286.4×10−3L = \frac{2 \times 64 \times 10^{-3}}{(80 \times 10^{-3})^2} = \frac{0.128}{6.4 \times 10^{-3}}
  3. L=20L = 20 H
  4. So the answer is (c) 2020 H.
Report a mistake

More questions on Other: Induction & Displacement Current