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MHT CET 2019 (2 May, Shift 2) · Magnetisation: B, H, M, χ & μ

Magnetisation: B, H, M, χ & μ question from MHT CET 2019 (2 May, Shift 2)

Q43MHT CET 2019 · 2 MAY · SHIFT 2Easy

Magnetisation: B, H, M, χ & μ

The magnetization of bar magnet of length 5 cm, cross sectional area 2 cm22\text{ cm}^2 and net magnetic moment 1 Am21\text{ Am}^2 is

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Answer: (d)

  1. Mz=mVM_z = \dfrac{m}{V}, V=5×2=10 cm3=10−5 m3V = 5\times2 = 10\text{ cm}^3 = 10^{-5}\text{ m}^3.
  2. Mz=110−5=1×105 A/mM_z = \dfrac{1}{10^{-5}} = 1\times10^{5}\text{ A/m}
  3. So the answer is (d).
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