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NEET 2012 (AIPMT, Prelims) · Optical Instruments & the Eye

Optical Instruments & the Eye question from NEET 2012 (AIPMT, Prelims)

Q49NEET 2012 · AIPMT · PRELIMSEasy

Optical Instruments & the Eye

The magnifying power of a telescope is 9. When it is adjusted for parallel rays the distance between the objective and eyepiece is 20 cm. The focal length of lenses are

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Answer: (c)

$\dfrac{f_o}{f_e} = 9$ and $f_o + f_e = 20\,\text{cm}$ .
$10f_e = 20 \Rightarrow f_e = 2\,\text{cm},\ f_o = 18\,\text{cm}$
So the answer is (c) 18 cm, 2 cm.

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