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MHT CET 2019 (3 May, Shift 1) · Optical Instruments & the Eye

Optical Instruments & the Eye question from MHT CET 2019 (3 May, Shift 1)

Q35MHT CET 2019 · 3 MAY · SHIFT 1Easy

Optical Instruments & the Eye

The magnifying power of a telescope is nine. When it is adjusted for parallel rays, the distance between the objective and eyepiece is 20 cm. The focal length of objective and eyepiece are respectively

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Answer: (b)

$\dfrac{f_o}{f_e} = 9$ and $f_o + f_e = 20\,\text{cm}$ .
$10f_e = 20 \Rightarrow f_e = 2\,\text{cm},\ f_o = 18\,\text{cm}$
So the answer is (b) 18 cm, 2 cm.

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